Answer
First three terms: $-4,-8,-12$
last term: $-200$
Sum of an arithmetic series: $-5100$
Work Step by Step
First three terms can be found as:$a_1=-4=4;a_2=-8;a_3=-12$
Last term can be found as: $a_{50}=-4(50)=-200$
Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(a_1+a_n)$
Here $n=50$
Thus,
$S_{50}=\dfrac{50}{2}(-4-200)=-5100$
our results are:
First three terms: $-4,-8,-12$
last term: $-200$
Sum of an arithmetic series: $-5100$
