Answer
Radius:$r=3$ and center: $(a,b)=(-2,3)$
Work Step by Step
Use standard form of equation of circles; $(x-a)^2+(y-b)^2=r^2$
Here, $r$ defines radius and $(a,b)$ defines center.
Then, $(x-(-2))^2+(y-3)^2=(3)^2$
Thus, on comparing the above equation with the standard form, we have
Radius:$r=3$ and center: $(a,b)=(-2,3)$
