Answer
$(x+2)^2+(y-4)^2=36$
Work Step by Step
Use standard form of equation of circles; $(x-a)^2+(y-b)^2=r^2$
Here, $r$ defines radius and $(a,b)$ defines center.
Thus, $(x-(-2))^2+(y-4)^2=(6)^2$
or, $(x+2)^2+(y-4)^2=36$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Review Exercises - Page 816: 6
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