Answer
$$\frac{y^{6}}{64x^{8}}$$
Work Step by Step
$$(8x^{4}y^{-3})^{-2}$$
Recall the power rule: $(a^{m})^{n}=a^{mn}$
Thus,
$$(8x^{4}y^{-3})^{-2} = (8^{-2}x^{4(-2)}y^{-3(-2)})$$
$$=(8^{-2}x^{-8}y^{6})$$
Recall the negative exponent rule: $a^{−n}=\frac{1}{a^{n}}$
Thus,
$$(8^{-2}x^{-8}y^{6})= \frac{y^{6}}{8^{2}x^{8}}$$
$$\frac{y^{6}}{64x^{8}}$$
