Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 5 - Exponential Functions - 5.5 Exponential Growth and Decay Rates and Compounding Interest - 5.5 Exercises - Page 469: 4

Answer

$46\%$ growth.

Work Step by Step

Growth or decay rate $r=b-1$ where $r$ is a percentage written as a decimal and $b$ is the base of an exponential function of the form $h(x)=a\cdot b^{x}$. Given $h(x)=3(1.46)^{x}$ $\implies b=1.46$ $r=b-1=1.46-1=0.46$ Or $r=0.46\times100 \%=46\% $ $r$ is positive. So, there is $46\%$ growth.
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