Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.7 Functions and Function Notation - 1.7 Exercises - Page 110: 63

Answer

a. $h(105)=1970$ b. $x= -\frac{320}{7}$ c. Domain:- $(-\infty,\infty)$. Range:- $(-\infty,\infty)$.

Work Step by Step

The given function is $h(x)=14x+500$ a. Substitute $x=105$ into the function. $\Rightarrow h(105)=14(105)+500$ Clear the parentheses. $\Rightarrow h(105)=1470+500$ Add. $\Rightarrow h(105)=1970$. b. Substitute $h(x)=-140$ into the function. $\Rightarrow -140=14x+500$ Subtract $500$ from both sides. $\Rightarrow -140-500=14x+500-500$ Simplify. $\Rightarrow -640=14x$ Divide both sides by $14$. $\Rightarrow \frac{-640}{14}={14x}{14}$ Simplify. $\Rightarrow -\frac{320}{7}=x$. c. This is a linear function. Hence, all real number inputs will result in real number outputs. The domain is $(-\infty,\infty)$. and the range is $(-\infty,\infty)$.
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