Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 598: 5

Answer

$(g\circ h)(x)=x^2-6x-2$

Work Step by Step

Since $(g\circ h)(x) = g(h(x))$, then, \begin{array}{l} (g\circ h)(x)=g(x^2-6x+5)\\\\ (g\circ h)(x)=x^2-6x+5-7\\\\ (g\circ h)(x)=x^2-6x-2 .\end{array}
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