Answer
$(f\circ h)(0)=5$
Work Step by Step
Since $(f\circ h)(0) = f(h(0))$, then,
\begin{array}{l}
(f\circ h)(0)=f(0^2-6(0)+5)\\\\
(f\circ h)(0)=f(5)\\\\
(f\circ h)(0)=5
.\end{array}
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