Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 598: 3

Answer

$(f\circ h)(0)=5$

Work Step by Step

Since $(f\circ h)(0) = f(h(0))$, then, \begin{array}{l} (f\circ h)(0)=f(0^2-6(0)+5)\\\\ (f\circ h)(0)=f(5)\\\\ (f\circ h)(0)=5 .\end{array}
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