Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms - Page 579: 2

Answer

$-x^{2}+x-7$

Work Step by Step

We know that $(f-g)(x)=f(x)-g(x)$. Therefore, $(f-g)(x)=f(x)-g(x)=(x-6)-(x^{2}+1)=-x^{2}+x+(-6-1)=-x^{2}+x-7$.
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