Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms - Page 579: 1

Answer

$x^{2}+x-5$

Work Step by Step

We know that $(f+g)(x)=f(x)+g(x)$. Therefore, $(f+g)(x)=f(x)+g(x)=(x-6)+(x^{2}+1)=x^{2}+x+(-6+1)=x^{2}+x-5$.
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