Answer
$pH =2.3$
Work Step by Step
$pH = -log_{10} (H+)$
$H+ = .005$
$pH = -log_{10} (H+)$
$pH = -log_{10} (.005)$
$-10^{pH} = .005$
$-1*-10^{pH} = .005*-1$
$10^{pH}=-.005$
$pH =2.3$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set - Page 573: 108
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