Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.4 - Exponential Growth and Decay functions - Exercise Set - Page 564: 17

Answer

There will be around 333 bison after 10 years.

Work Step by Step

This involves exponential growth as the population will increase by 2.5 percent annually. RECALL: Exponential growth is represented by the formula $y=C(1+r)^x$ where C = initial/original amount r = growth rate x = number of time intervals The given situation has: C = 260 r = $2.5\%$ per year x = 10 years Substitute these values into the given formula above to have: $y=260(1+2.5\%)^{10} \\y=260(1+0.025)^{10} \\y260(1.025^{10}) \\y \approx 333$
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