Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 326: 108

Answer

Incorrect

Work Step by Step

The given step is incorrect because when the product of factors is equal to $6,$ it does not necessarily mean that one of the factors is $6.$ (The product of $3$ and $2$ is equal to $6,$ but none of the factors is equal to $6.$)
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