Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 326: 103

Answer

$x=\left\{ \dfrac{4}{3},7 \right\}$

Work Step by Step

Substituting $y$ with $317$ in $ y=3x^2-25x+345 ,$ then \begin{array}{l}\require{cancel} 317=3x^2-25x+345 .\end{array} Using the properties of equality, the equation above is equivalent to \begin{array}{l}\require{cancel} 3x^2-25x+345-317=0 \\ 3x^2-25x+28=0 \\ (3x-4)(x-7)=0 .\end{array} Equating each factor to zero (Zero Product Property) then the solutions of the equation above are $ x=\left\{ \dfrac{4}{3},7 \right\} .$
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