Answer
$x=\left\{ -\dfrac{1}{3},0 \right\}$
Work Step by Step
The factored form of the given expression, $
m^2(3m-2)=m
$, is
\begin{array}{l}
3m^3-2m^2-m=0
\\\\
m(3m^2-2m-1)=0
\\\\
m(3m+1)(m-1)=0
.\end{array}
Equating each factor to zero, then
\begin{array}{l}
m=0
,\text{ OR}\\\\
3m+1=0
\\
3m=0-1
\\
3m=-1
\\
m=-\dfrac{1}{3}
\end{array}
Hence, $
x=\left\{ -\dfrac{1}{3},0 \right\}
$.
