Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.8 - Solving Equations by Factoring and Problem Solving - Exercise Set - Page 323: 33

Answer

{-3, 5}

Work Step by Step

1. Factor the expression. $x^{2}$ - 2x - 15 = (x - 5)(x + 3) 2. Apply the zero factor property. a) x -5 = 0 b) x + 3 = 0 3. Solve each equation. a) x = 5 b) x = -3 The solutions are {-3, 5}.
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