Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 99b

Answer

$F(a)=a^2+3a+2$

Work Step by Step

Replacing $x$ with $a$ in the given function, $ F(x)=x^2+3x+2 $, then $F(a)$ is equal to \begin{array}{l} (a)^2+3(a)+2 \\\\= a^2+3a+2 \end{array}
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