Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Exercise Set - Page 290: 115

Answer

$x^3+5x^2-2x-10$

Work Step by Step

Using the given functions, then, \begin{align*} R(x)\cdot Q(x)=(x+5)(x^2-2) \\= (x)(x^2)+(x)(-2)+(5)(x^2)+(5)(-2) \\= x^3-2x+5x^2-10 \\= x^3+5x^2-2x-10 .\end{align*}
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