Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 333: 28

Answer

$(2,0)$

Work Step by Step

$4x-2y=8$ Equation $(1)$ $y= 3x-6$ Equation $(2)$ Substituting $y$ from Equation $(2)$ in Equation $(1)$ $4x-2y=8$ $4x-2(3x-6)=8$ $4x-6x+12 = 8$ $-2x+12 = 8$ $-2x = 8 -12$ $-2x = -4$ $x = \frac{-4}{-2}$ $x = 2$ Substituting $x$ value in Equation $(2)$ to get $y$ $y= 3x-6$ $y= 3(2)-6$ $y= 6-6$ $y = 0$ Solution: $(2,0)$
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