Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review - Page 333: 27

Answer

Solution: $(-4,\frac{1}{2})$

Work Step by Step

$2x+4y = -6$ Equation $(1)$ $x= 2y-5$ Equation $(2)$ Substituting $x$ from Equation $(2)$ in Equation $(1)$ $2x+4y = -6$ $2(2y-5)+4y=-6$ $4y-10+4y = -6$ $8y-10= -6$ $8y = -6+10$ $8y = 4$ $y= \frac{4}{8}$ $y= \frac{1}{2}$ Substituting $y$ value in Equation $(2)$ to get $x$ $x= 2y-5$ $= 2( \frac{1}{2})-5$ $ = 1-5$ $x = -4$ Solution: $(-4,\frac{1}{2})$
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