Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - Test: Chapter 2 - Page 151: 19

Answer

$l=2w-P$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To solve the given equation, $ w=\dfrac{P+l}{2} $ for $ l ,$ use the properties of equality to isolate the variable. $\bf{\text{Solution Details:}}$ Using the properties of equality to isolate the variable, the equation above is equivalent to \begin{array}{l}\require{cancel} w=\dfrac{P+l}{2} \\\\ 2(w)=2\left( \dfrac{P+l}{2} \right) \\\\ 2w=P+l \\\\ 2w-P=l \\\\ l=2w-P .\end{array}
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