Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set - Page 95: 99

Answer

$0.\overline{1}$

Work Step by Step

Dividing the numerator by the denominator, then the given expression, $ -\dfrac{1}{9} $, is equivalent to \begin{array}{l}\require{cancel} 0.\overline{1} .\end{array}
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