Answer
$c=1$
Work Step by Step
Using the properties of equality, the solution to the given equation, $
13-(2c+2)=2(c+2)+3c
$, is
\begin{array}{l}
13-2c-2=2c+4+3c
\\\\
11-2c=5c+4
\\\\
-2c-5c=4-11
\\\\
-7c=-7
\\\\
c=\dfrac{-7}{-7}
\\\\
c=1
.\end{array}
CHECKING:
\begin{array}{l}
13-(2\cdot1+2)=2(1+2)+3\cdot1
\\\\
13-(4)=2(3)+3
\\\\
9=6+3
\\\\
9=9
\text{ (TRUE)}
.\end{array}
Hence, the solution is $
c=1
$.
