Answer
$S_n=n^2$
Work Step by Step
We have to find a formula for the sum of the first n consecutive odd numbers starting with $1$:
$1+3+5+ . . . +(2n-1)$
We have an arithmetic sequence with
$a_1=1$,
$d=2$ and
$a_n=(2n-1)$
The sum
$S_n=\dfrac{a_1+a_n}{2}n=\dfrac{1+2n-1}{2}n=n^2$