Answer
$x^2+y^2=16$
Work Step by Step
The standard equation of the circle has the form
$(x-x_0)^2+(y-y_0)^2=R^2,$
where $(x_0,y_0)$ is centre coordinate and $R$ - radius.
In our case $x_0=0, y_0=0$ and $R=4$. Hence the circle's equation is:
$$x^2+y^2=16$$