Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.7 Applications of Exponential Functions and Logarithmic Functions - 12.7 Exercise Set - Page 837: 48

Answer

The linear function whose graph contains the points $\left( 6,11 \right)$ and $\left( -6,-11 \right)$ is $y=\frac{11}{6}x$.

Work Step by Step

First calculate the slope: Substitute $-11$ for ${{y}_{2}}$, $11$ for ${{y}_{1}}$, $-6$ for ${{x}_{2}}$ and $6$ for ${{x}_{1}}$ in $m=\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$, $\begin{align} & m=\frac{-11-11}{-6-6} \\ & =\frac{-22}{-12} \\ & =\frac{11}{6} \end{align}$ Substitute $6$ for ${{x}_{1}}$, $11$ for ${{y}_{1}}$ and $\frac{11}{6}$ for $m$. $\begin{align} & y-11=\frac{11}{6}\left( x-6 \right) \\ & y-11=\frac{11}{6}x-11 \end{align}$ $y=\frac{11}{6}x$
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