Answer
$\log_{t}{3}+\log_{t}{a}+\log_{t}{b}$
Work Step by Step
Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $
\log_{t}{(3ab)}
,$ is equivalent to
\begin{array}{l}\require{cancel}
\log_{t}{3}+\log_{t}{a}+\log_{t}{b}
.\end{array}
