Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.4 Properties of Logarithmic Functions - 12.4 Exercise Set - Page 809: 10

Answer

$\log_{5}{25}+\log_{5}{125}$

Work Step by Step

Using $\log_b(xy)=\log_b x +\log_b y,$ the given logarithmic equation, $ \log_{5}{(25\cdot125)} ,$ is equivalent to \begin{array}{l}\require{cancel} \log_{5}{25}+\log_{5}{125} .\end{array} This can be further reduced to 2+3. Therefore, the expression is equal to 5.
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