Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 77: 71

$25,281$

Substituting $a=1$ and $b=2$ in the given expression, $ a^{50}-20a^{25}b^4+100b^8 ,$ results to \begin{array}{l}\require{cancel} a^{50}-20a^{25}b^4+100b^8 \\\\= (1)^{50}-20(1)^{25}(2)^4+100(2)^8 \\\\= (1)-20(1)(16)+100(256) \\\\= 1-320+25600 \\\\= 25,281 .\end{array}