Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1 - Page 76: 41

Answer

$-\dfrac{7}{12}$

Work Step by Step

The given expression, $ -\dfrac{2}{3}+\dfrac{1}{12} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{4(-2)+1(1)}{12} \\\\= \dfrac{-8+1}{12} \\\\= \dfrac{-7}{12} \\\\= -\dfrac{7}{12} .\end{array}
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