Answer
$\dfrac{3}{5}$
Work Step by Step
Using the $LCD=
15
$, the given expression, $
\dfrac{2}{3}-\dfrac{1}{15}
$, simplifies to
\begin{array}{l}\require{cancel}
\dfrac{5(2)-1(1)}{15}
\\\\=
\dfrac{10-1}{15}
\\\\=
\dfrac{9}{15}
\\\\=
\dfrac{\cancel{3}\cdot3}{\cancel{3}\cdot5}
\\\\=
\dfrac{3}{5}
.\end{array}
