Answer
$2+\sqrt[3]{20}$
Work Step by Step
Using $a(b+c)=ab+ac$, or the Distributive Property, and the properties of radicals, the given expression, $
\sqrt[3]{2}(\sqrt[3]{4}+\sqrt[3]{10})
,$ simplifies to
\begin{array}{l}\require{cancel}
\sqrt[3]{2}(\sqrt[3]{4})+\sqrt[3]{2}(\sqrt[3]{10})
\\\\=
\sqrt[3]{8}+\sqrt[3]{20}
\\\\=
\sqrt[3]{(2)^3}+\sqrt[3]{20}
\\\\=
2+\sqrt[3]{20}
.\end{array}