Answer
$= \frac{x}{(x+3)}$
Work Step by Step
$\frac{x^{2}-9x}{x^{2}-6x-27}$
1. Factor the numerator:
$= \frac{x(x-9)}{x^{2}-6x-27}$
2. Factor the denominator:
$= \frac{x(x-9)}{(x-9)(x+3)}$
3. Cancel out $x-9$ as both the numerator and denominator contains that component:
$= \frac{x}{(x+3)}$
