Chapter 7 - Algebraic Fractions - 7.5 - Fractional Equations and Problem Solving - Problem Set 7.5 - Page 306: 33

$x = -1$

1. Multiply by $x+2$ on both sides of the equation to obtain: $\frac{x}{x+2} + 3 = \frac{2}{x+2}$ $x + 3(x+2) = \frac{2(x+2)}{x+2}$ 2. Cancel out $x+2$ in the fraction to simplify: $x + 3(x+2) = 2$ 3. Expand and solve for $x$ $x + 3x + 6 = 2$ $4x + 6 - 2 = 0$ $4x + 4 = 0$ $4(x + 1) = 0$ $x + 1 = 0$ $x = -1$