Answer
$n = 6$
Work Step by Step
1. Multiply by $n$ on both sides of the equation to remove the fractions:
$\frac{51-n}{n} = 7 + \frac{3}{n}$
$51-n = 7n + \frac{3n}{n}$
2. Cancel out the $n$'s in the fraction:
$51 - n = 7n + 3$
3. Solve for $n$
$51 - n - 7n - 3 = 0$
$48 - 8n = 0$
$8(6 - n) = 0$
$6 - n = 0$
$-n = -6$
$n = 6$
