Answer
$-n-1$
Work Step by Step
By inspection, we see that there is a common denominator of $6$. Therefore, we obtain:
$\frac{3n-7}{6}-\frac{9n-1}{6}$
=$\frac{3n-7-(9n-1)}{6}$
=$\frac{3n-7-9n+1}{6}$
=$\frac{-6n-6}{6}$
=$\frac{6(-n-1)}{6}$
=$-n-1$
