Answer
$2$
Work Step by Step
By inspection, we see that there is a common denominator of $x$. Therefore, we obtain:
$\frac{2x+3}{x}-\frac{3}{x}$
=$\frac{(2x+3)-(3)}{x}$
=$\frac{2x+3-3}{x}$
=$\frac{2x}{x}$
=$2$
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