Answer
$\frac{(n+3)}{n}$
Work Step by Step
We factor the expression in the denominator by taking out $n$ as the common factor. Since the numerator consists of a trinomial, we use the rules of factoring trinomials in order to factor it. Then, we cancel out the resultant common factors in the numerator and the denominator:
$\frac{n^{2}+9n+18}{n^{2}+6n}$
=$\frac{n^{2}+3n+6n+18}{n(n+6)}$
=$\frac{n(n+3)+6(n+3)}{n(n+6)}$
=$\frac{(n+3)(n+6)}{n(n+6)}$
=$\frac{(n+3)}{n}$
