Answer
True
Work Step by Step
We use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ to help us cancel out the common factors of $x$ in the numerator and the denominator:
$\frac{-5x^{2}y}{10x}$
=$\frac{-5}{10}\times \frac{x^{2}}{x}\times y$
=$\frac{-1}{2}\times x^{2-1}\times y$
=$-\frac{1}{2}\times x\times y$
=$-\frac{xy}{2}$
Since this answer matches the one in the statement, the statement is true.