Answer
True
Work Step by Step
We use the rule $\frac{a^{m}}{a^{n}}=a^{m-n}$ to help us cancel out the common factors of $y$ in the numerator and denominator:
$\frac{12xy^{3}}{-16y^{2}}$
=$\frac{12}{-16}\times x\frac{y^{3}}{y^{2}}$
=$\frac{3}{-4}\times x\times y^{3-2}$
=$-\frac{3}{4}\times x\times y$
=$-\frac{3xy}{4}$
Since this answer matches the one in the statement, the statement is true.
