Answer
{$\frac{7}{5}$}
Work Step by Step
Using the rules of factoring trinomials to factor the polynomial, we obtain:
$25n^{2}-70n+49=0$
$25n^{2}-35n-35n+49=0$
$5n(5n-7)-7(5n-7)=0$
$(5n-7)(5n-7)=0$
Now, we equate the two factors to zero and solve:
$(5n-7)(5n-7)=0$
$(5n-7)=0$ or $(5n-7)=0$
$n=\frac{7}{5}$ or $n=\frac{7}{5}$
Therefore, the solution set is {$\frac{7}{5}$}.
