Answer
{$0,8$}
Work Step by Step
Since $4n$ is common to both the terms of the equation, we take it out as a common factor:
$4n^{2}=32n$
$4n^{2}-32n=0$
$4n(n-8)=0$
Now, we equate all the factors to zero to solve the equation:
$4n(n-8)=0$
$4n=0$ or $(n-8)=0$
$n=0$ or $n=8$
Therefore, the solution set is {$0,8$}.
