Answer
The solution set is $\left\{-2, 8\right\}$.
Work Step by Step
Multiply $-1$ on both sides of the equation to obtain:
$x^2-6x-16=0$
Factor the trinomial by looking for the factors of $-16$ whose sum is equal to the coefficient of the middle term ($-6$).
These factors are $-8$ and $2$. This means that the factored form of the trinomial is $(x-8)(x+2)$.
Thus,
$x^2-6x-16=0
\\(x-8)(x+2)=0$
Equate each factor to 0; then simplify to obtain:
$x-8=0 \text{ or } x+2=0
\\x=8 \text{ or } x=-2$
The solution set is $\left\{-2, 8\right\}$.
