Answer
This expression is not factorable using integers.
Work Step by Step
To factor a trinomial in the form $x^2+bx+c$, we must find two numbers whose product is $c$ and whose sum is $b$. We then insert these two numbers into the blanks of the factors $(x+\_)(x+\_)$.
In the case of $x^2-10x-48$, we are looking for two numbers whose product is $-48$ and whose sum is $-10$. Unfortunately, there are no integers that meet these criteria, so this expression is not factorable using integers.