Answer
The largest possible value for the width of the rectangle is 15 inches.
Work Step by Step
Let w represent the width of the rectangle.
The perimeter of the rectangle = width + width + length + length
The perimeter of the rectangle = w + w + 20 + 20
The perimeter of the rectangle = 2w + 40
The perimeter should not be greater than 70, which means 2w + 40 $\leq$ 70.
We solve this inequality to obtain:
2w + 40 $\leq$ 70
2w $\leq$ 30
Divide both sides by 2.
w $\leq$ 15
The maximum value the width can be is 15.
