Answer
All numbers greater than or equal to 14 satisfy this relationship.
The solution set is {x|x $\geq$ 14 } , or [14,$\infty$) in interval notation.
Work Step by Step
Let x represent the numbers that satisfy this relationship.
Fourteen increased by twice a number means 14 + 2x.
Less than or equal means $\leq$.
Three times the number means 3x.
So, we need to solve 14 + 2x $\leq$ 3x
14 + 2x $\leq$ 3x
Subtract 2x from both sides.
14 $\leq$ x
All numbers greater than or equal to 14 satisfy this relationship.
The solution set is {x|x $\geq$ 14 } , or [14,$\infty$) in interval notation.
