Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 137: 6

y=40/3

We first use the distributive property to obtain that $7y-28=4y+12$. We need to get the y alone, so we cancel out the subtraction by adding 28 on both sides. This leaves us with the equation 7y=4y+40. We then subtract by 4y on both sides to find that $3y=40$. We use division to cancel out multiplication, so we divide both sides by 3 to get that $y=40/3$.