Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 137: 15

Answer

$n=21$

Work Step by Step

Using the properties of equality, the value of the variable that satisfies the given equation, $ 5(n-1)-4(n+2)=-3(n-1)+3n+5 ,$ is \begin{array}{l}\require{cancel} 5n-5-4n-8=-3n+3+3n+5 \\\\ 5n-4n+3n-3n=3+5+5+8 \\\\ n=21 .\end{array}
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