Answer
$= \frac{35y + 27}{21y^{2}}$
Work Step by Step
1) Find a common denominator: Multiply the first fraction by $7y/7y$ and the second fraction by $3/3$ to obtain a common denominator of $21y^{2}$
2) Add the fractions
$= \frac{5}{3y} + \frac{9}{7y^{2}}$
$= \frac{5(7y)}{21y^{2}} + \frac{9(3)}{21y^{2}}$
$= \frac{35y}{21y^{2}} + \frac{27}{21y^{2}}$
$= \frac{35y + 27}{21y^{2}}$
