Answer
$= \frac{4y}{5}$
Work Step by Step
First, multiply the numerators and the denominators by each other. Next, cancel out common factors to obtain:
$= \frac{8x}{15y} \times \frac{9y^{2}}{6x}$
$= \frac{72xy^{2}}{90xy}$
$= \frac{4y}{5}$
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